A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point (6i – 8j) m. How much work is done by the given force during this displacement?
a. +60 J b. +84 J c. +72 J d. +48 J e. +57 J
ok...
the work done is F.r so we give F and r in vector form...
F= 12i N , r = 6i - 8j m
thus :
W = 12i . (6i - 8j) = 72J
notice that the mass of the body is not required in the calculations here
thanks