[المتفيزق]

A particle starts from the origin at t = 0 with a velocity of 6.0i m/s and moves in the xy plane with a constant acceleration of (–2.0i + 4.0j) m/s2. At the instant the particle achieves its maximum positive x coordinate, how far is it from the origin?
yes,
the particle reaches its max. point when vx =0 i.e.
0=6-2t or t = 3 sec.
that is ;
at this time: x=6*3-0.5*2*9=9 m
and y = 0+0.5*4*9=18m
this means that its position is now:
r = 9i +18j
thanks