[m2007]

السلام عليكم ورحمة الله وبركاته

لو سمحتم اريد منكم حل هذه الاسئلة لمن يعرف الحل وجزيتم خيرا

Question1:
A parallel-plate capacitor with circular shaped plates, with a diameter of 4 cm and air-gap separation of 0.50 mm is connected to a 12 V battery, and fully charged. The battery is then disconnected, what is the charge on the capacitor?
Question 2:
Consider a charged parallel-plate capacitor. How can its capacitance be halved? Check all that apply from the list below and show how:

- Double the charge.
- Double the plate area.
- Double the plate separation.
- Halve the charge.
- Halve the plate area.
- Halve the plate separation.
Question 3:
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance and show how?
- Double the charge and double the plate area.
- Double the charge and double the plate separation.
- Halve the charge and double the plate separation.
- Halve the charge and double the plate area.
- Halve the plate separation and double the plate area.
- Double the plate separation and halve the plate area.

Question 4:
A parallel plate capacitor is formed from two square pieces of metal 0.040 m on a side. The plates are separated by 0.008 m, and the space between them is filled with insulating rubber, which has a dielectric constant of 6.7. When this capacitor is connected to a 25 volt battery, what is the magnitude of the charge on each plate?